{"id":1144,"date":"2013-06-25T12:07:23","date_gmt":"2013-06-25T04:07:23","guid":{"rendered":"http:\/\/rais.my\/blog\/?p=1144"},"modified":"2013-06-25T15:06:44","modified_gmt":"2013-06-25T07:06:44","slug":"1-2-berapa","status":"publish","type":"post","link":"https:\/\/rais.my\/blog\/1-2-berapa\/","title":{"rendered":"1 + 2 Berapa???"},"content":{"rendered":"

Assalam,<\/p>\n

Simple matematik.\u00a01 + 2 semestinya 3.<\/p>\n

Bagaimana kalau 1 + 2 + 3? Mudah juga. Mestilah 6.<\/p>\n

Kalau 1 + 2 + 3 +4 +5? Sonang juga… 55….<\/p>\n

Ok, kalau 1 + 2 + 3 + 4 + 5 ……… + 100, Eeerrrrr jap ambil kalkulator…..<\/p>\n

Sebenarnya ada cara cepat dan mudah iaitu guna kan formula.<\/p>\n

Hasil tambah 1 hingga n = n(n+1)\/2, n ialah bilangan sehingga ke n.<\/p>\n

Mari kita cuba,\u00a01 + 2 + 3 + 4 + 5 ……… + 100<\/p>\n

= n(n+1)\/2
\n=100(100+1)\/2
\n= 100(101)\/2
\n= 10100\/2
\n= 5050 #<\/p>\n

\"formula-150x150<\/a><\/p>\n

Sekarang kita lihat bagaimana formula ini terhasil.<\/p>\n

Katakan
\nn = 1 + 2 + 3 … sehingga … + n ialah<\/p>\n

n = 1 + 2 + 3 ….. (n – 2) + (n – 1) + n
\nDan sama juga dengan
\nn = n + (n – 1) + (n – 2) ….. 3 + 2 + 1<\/p>\n

Sekiranya digabungkan dua formula tersebut dengan menambahnya, kita dapat
\n2n = (n + 1) + (n – 1 + 2) + (n – 2 + 3) ….. +\u00a0(n – 2 + 3) +\u00a0(n – 1 + 2) + (n + 1)
\n2n = (n + 1) +\u00a0(n + 1) +\u00a0(n + 1) ….. +\u00a0(n + 1) +\u00a0(n + 1) +\u00a0(n + 1)
\n2n =\u00a0(n + 1) di tambah sehingga ke bilangan ke-n
\n2n = n(n + 1)
\nn = n(n + 1)\/2 #<\/p>\n

Moga perkongsian ini kita dapat lihat cantiknya matematik…..<\/p>\n

rais.my<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Assalam, Simple matematik.\u00a01 + 2 semestinya 3. Bagaimana kalau 1 + 2 + 3? Mudah juga. Mestilah 6. Kalau 1 + 2 + 3 +4 +5? Sonang juga… 55…. Ok, kalau 1 + 2 + 3 + 4 + 5 ……… + 100, Eeerrrrr jap ambil kalkulator….. Sebenarnya ada cara cepat dan mudah iaitu guna […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"cybocfi_hide_featured_image":"","footnotes":""},"categories":[88,483,1],"tags":[606,610,675,608,609,607],"class_list":["post-1144","post","type-post","status-publish","format-standard","hentry","category-hobi","category-matematik","category-umum","tag-1234-n","tag-formula","tag-matematik","tag-math","tag-mathematic","tag-nn-12"],"_links":{"self":[{"href":"https:\/\/rais.my\/blog\/wp-json\/wp\/v2\/posts\/1144","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/rais.my\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/rais.my\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/rais.my\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/rais.my\/blog\/wp-json\/wp\/v2\/comments?post=1144"}],"version-history":[{"count":4,"href":"https:\/\/rais.my\/blog\/wp-json\/wp\/v2\/posts\/1144\/revisions"}],"predecessor-version":[{"id":1151,"href":"https:\/\/rais.my\/blog\/wp-json\/wp\/v2\/posts\/1144\/revisions\/1151"}],"wp:attachment":[{"href":"https:\/\/rais.my\/blog\/wp-json\/wp\/v2\/media?parent=1144"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/rais.my\/blog\/wp-json\/wp\/v2\/categories?post=1144"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/rais.my\/blog\/wp-json\/wp\/v2\/tags?post=1144"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}